when a car is making a turn and is at its maximum static friction, then any increase in centripetal acceleration will cause it to veer off its circular path.

If you increase v then the vehicle will go tangent to its circular path meaning it will slide outwards. What about if you decrease r?

Since decreasing r also increases centripetal acceleration, would you also go outwards when you turn the into the circle without static friction compensating it?

Question

when a car is making a turn and is at its maximum static friction, then any increase in centripetal acceleration will cause it to veer off its circular path. 

If you increase v then the vehicle will go tangent to its circular path meaning it will slide outwards. What about if you decrease r? 

Since decreasing r also increases centripetal acceleration, would you also go outwards when you turn the into the circle without static friction compensating it?

anonymous · Answer

never mind. I got it. the answer is that the car would skid tangentially (outwards) with decreasing radius once the centripetal force exceeds the static friction.