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Multiply, using special product methods. ( x-5)^2 Medal will be given.
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hint: \[\Large (a-b)^2 = a^2 - 2ab + b^2\]
whats next?
what are a and b in this case?
a is x and b is -5 ?
well when talking about (a-b)^2, b is +5, but I see how you got -5
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so... \[\Large (a-b)^2 = a^2 - 2ab + b^2\] \[\Large (x-5)^2 = x^2 - 2*x*5 + 5^2\] \[\Large (x-5)^2 = x^2 - 10x + 25\]
so you solve the last part or just leave it like that?
what do you mean?
the 3rd statement
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