Question

What is the equation in point-slope form of the line passing through (-2, 0) and (2, 8)?

Answer 1

y2-y1/x2-x1

Answer 2

y2-y1/x2-x1=Slope
so 8-0/2-(-2)

Answer 3

you can find the slope of the line by following formula. \[m= \frac{ y_{2}- y_{1} }{ x_{2}- x_{1} } = \frac{ 8-0 }{ 2-(-2) } = \frac{ 8 }{ 4 } = 2\]

and now equation is \[(y-y _{1}) = m (x-x _{1}) \]

\[(y-0) = 2 (x + 2) \implies y = 2x+ 4 \]

Answer 4

same copy @Smg93

Answer 5

so would it be y=-2(x-2)?

Answer 6

no @Tfinley2013

you can crosscheck by substituting points in \[y = 2x + 4\]

it will satisfy, but it wont satisfy your equation.

Answer 7

so would it be y=2(x+2) ?