Question

I need help with this problem

Answer 1

w.t.fuge I don't get it?

Answer 2

To simplify things, we only consider the part of the graph which lies in the first quadrant.
Now y=|x| becomes y=x since x>0
Since the two graphs only touch each other: x=0.050x^2+k
Treat k like a constant.
Find the determinant and equate it to 0.
This will give you the value of k

Answer 3

How do I find the determinant?

Answer 4

Sorry, I mean the discriminant. :(
The equation is 0.050x^2-x+k=0
Ok, so delta=b^2-4ac=(-1)^2-4*0.050*k
Equate this to 0, and you'll get k.

Answer 5

Thanks, got it