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find the vertex of y=x^2-14x+49
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convert x^2 - 14x into the form (x - a)^2 - a^2 where a = 14/ 2 then add the 49
the last number will give you the y coordinate of the vertex
I did. im still getting the incorrect answer
(x - 7)^2 - 49 + 49
= (x -7)^2 + 0 the vertex is at (7,0)
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oh wow ! I figure that was it! I did something wrong but that is one of my multiple choice answer. thanks !!
thats ok - the x-coordinate is the value of a in (x -a)^2
ok I see now. thanks
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