I know how to find slope but idk how to figure this out. someone help!

The equation of line AB is y = 5x + 1. Write an equation of a line parallel to line AB in slope-intercept form that contains point (4, 5).

y = 5x − 15

y = 5x + 15

y = 1 over 5x + 21 over 5

y = 1 over 5x − 29 over 5

I know how to find slope but idk how to figure this out. someone help!

Question

I know how to find slope but idk how to figure this out. someone help!

The equation of line AB is y = 5x + 1. Write an equation of a line parallel to line AB in slope-intercept form that contains point (4, 5).

 y = 5x − 15

 y = 5x + 15

 y = 1 over 5x + 21 over 5

 y = 1 over 5x − 29 over 5




I know how to find slope but idk how to figure this out. someone help!

texaschic101 · Answer

y = 5x + 1
The slope of this line is 5.
A parallel line will have the same slope.

Now use y = mx + b, and sub in our slope(m) = 5 and our points (4,5) into the formula and solve for b (the y intercept)

y = mx + b
5 = 4(5) + b
5 = 20 + b
5 - 20 = b
- 15 = b

Therefore, our parallel line is : y = 5x - 15

anonymous · Answer

thank you so much !! it means a lot

texaschic101 · Answer

do you understand everything or do you have any questions ?

anonymous · Answer

no thank you, i understand the lesson now (:

texaschic101 · Answer

good to hear :) glad I could help