Question

solve |x/3+1|= 6

Answer 1

You mean this equation ?\[\left| \frac{ x }{ 3 }+1 \right|=6\]

Answer 2

yes

Answer 3

this is eassyy i know you can do this xD just eliminate everything except for x :) 6-1=5 now you have x/3=5 multiply 5x3 and you get 15 which is your answer :p

Answer 4

first we explicite the module=>\[\left| \frac{ x }{ 3 }+1 \right|=\left[\begin{matrix}\frac{ x }{ 3 }+1 (if),\frac{ x }{ 3 } +1>0 \\ \frac{ -x }{ 3 } -1 (if),\frac{ x }{ 3 }+1<0\end{matrix}\right]\]
I.if \[\frac{ x }{ 3 }+1>0\]=>x/3>-1=>x>-3=>x/3=5=>X=15
II.-x/3-1=6=>-x/3=7=>X=-21

Answer 5

remember you eliminate numbers by canceling them out :) @ifrimpanainte thats so confusing :o

Answer 6

confusing or not you're answer is wrong

Answer 7

X can be either 15 either -21

Answer 8

@erielle do you understand?

Answer 9

Yes thank you for answering :)