Question

Can someone explain to me how to "solve these systems algebraically"?

Example: 5x+2y=10
3x+2y=6

I think I understand; I just want to be sure.

This is in "Linear Systems" by the way.

Answer 1

#2. y=1.5x+3

Answer 2

Ok, so that's the answer to the second part? That's all one problem btw.

Answer 3

have you covered system of equations yet?

Answer 4

or is it just 2 separate fucntions:?

Answer 5

It's a linear system. I'm usually pretty good at this stuff but I'
m kind of lost here. lol

Answer 6

ok... lemme try to show it by means of elimination

Answer 7

\(\large \begin{array}{llll}
5x+2y=10&&\quad 5x\cancel{+2y}=10\\
3x+2y=6&{\color{red}{ \times -1}}\implies &-3x\cancel{-2y}=-6\\
\hline\\
&&\quad 2x\qquad\qquad =4
\end{array}\)

so as you can see what "x" is then
then you can just substitute that on either equation and solve for "y" to get "y"

Answer 8

Hmm... Ok, thanks man. :)