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Find the Legrangian point L1 between a planet and it's moon.
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Moon \(9.76\times10^{20}kg\) orbits \(1.20\times10^{7}m\) around the planet \(5.29\times10^{22}kg\). ?
|dw:1396425210400:dw|
is that one the one where the gravitational force between the planet and the object is exactly equal to the gravitational force between the moon and the object ?
Yeah, that makes sense.
actually thats not right , the gravitational attractions do not cancel exactly at the L_1 point
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it is more complicated than that, i think you have to use Kepler's third law,
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