Question

I = 4000 x ( 9 + 1)/100 x 3

Answer 1

I= 120

Answer 2

Is this the problem?

\(I = 4000 \times \dfrac{9 + 1}{100} \times 3\)

Answer 3

This is what you wrote above, so I'll help you with it.

\(I = 4000 \times \dfrac{9 + 1}{100} \times 3\)

First, you must do the addition in the numerator.

\(I = 4000 \times \dfrac{10}{100} \times 3\)

Now do the division in the fraction.

\(I = 4000 \times 0.1 \times 3\)

Now multiply the three numbers together.

\(I = 1200\)