Question

The slope of a line through (15, -8) that is perpendicular to the line with the equation y= 5x +9

Answer 1

if the lines are perp. then . slope of line 1 * slope of line 2 = -1

so, slope of line 1= -1/slope of line 2
= -1/5

now the equation of line 1 is

y-y1= slope * (x-x1)
=> y-(-8)=-1/5*(x-16)
=> y+8=(16-x)/5
=>5y+x-24=0

the desired equation is $$\huge \color {red}{5y+x-24=0}$$

Answer 2

sorry, I have taken x1 as 16. Do substitute it and do the calculations :P

Answer 3

If the slope of the line is -1/5 what is the y intercept

Answer 4

for the y intercept in the desired equation put x= 0 the value for y will give the y intercept ...

Answer 5

after plugging x1 as 15 u will get,

$$\huge \color{red}{5y+x-25=0}$$