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What is the solution to the equation log(4)x–log(4)2 = 2
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please thank you
start by using \[\log(a)-\log(b)=\log(\frac{a}{b})\] to write \[\log_4(\frac{x}{2})=2\] then write in equivalent logarithmic form as \[\frac{x}{2}=4^2\] then solve for \(x\)
you good from there?
how do i know which #s to put where?
not sure what you mean
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\[\large \log_b(z)=y\iff z=b^y\] you have \[\large \log_4(\frac{x}{2})=2\] which means \[\frac{x}{2}=4^2\]
so it's 32?
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