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log[log(x+4)]=0 what is value of x and how
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Say \(\log(x+4)=y\), then \(\log y = 0 \implies e^0 = y \implies y = 1\) Thus, \(\log(x+4)=1\), so \(e^1=x+4=\implies x=e-4\)
Oh wait actually, are you using log in base \(e\) or 10?
thanks bro i understand
log[log(x+4)-4]=0 then x=-4 how
o_O If you're in base \(e\), you should get \(e^5-4\). If you are in base 10, you should get \(10^5-4\).
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In fact, if x=-4 here, you get \(\log(\log(-4+4)-4)=\log(\log(0)-4)\) and \(\log0\) is undefined
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