A 30.0g ball of clay traveling east at 9.00m/s collides and sticks together with a 60.0g ball of clay traveling north at 3.00m/s . What is the speed of the resulting ball of clay
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OpenStudy (anonymous):
i'm not quite sure on this question. did you try looking it up on yahoo or google
OpenStudy (anonymous):
if not let me see wt i can do
OpenStudy (anonymous):
I know how to do the question if the directions were opposite but not perpendicular, i couldn't find anything on google
OpenStudy (anonymous):
yahoo
OpenStudy (anonymous):
Tried yahoo too
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OpenStudy (anonymous):
dang
OpenStudy (anonymous):
let me see if someone i know can help you
OpenStudy (anonymous):
so far i found the momentum of Ball 1 = (.03kg)(9m/s)= 0.27kg*m/s eastward
and the momentum of ball 2=(.06kg)(3m/s)=0.18kg*m/s northward
but Im not sure if to add or subtract them
OpenStudy (anonymous):
ok my friend will help you
OpenStudy (anonymous):
alright thank you
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OpenStudy (anonymous):
he said no bueno at math but i'll ask someone else who is good