Question

HELP... what is the slope of this line -16x+12y=0

Answer 1

First you need to put it into Y intercept form.. are you familiar with this?
y = mx + b

Answer 2

Ax+By=C
slope=-A/B

Answer 3

Start by isolating the y.
-16x + 12y = 0
12y = 16x
y = 16/12x
y = 4/3x

Answer 4

And since x is the slope, the slope of your line is 4/3.

Answer 5

4/3

Answer 6

\[Ax+By=C\]so A=-16, B=12, and C=0\[-16x+12y=0\]\[12y=16x+0\]\[y=\frac{4}{3}x\]now it is in the slope-intercept form, y=mx+b, and the slope is m. slo slope=4/3