Question

The area of a rectangle is 4,320 ft2. The ratio of the length to the width is 6:5. Find the length of the rectangle.

A.
12 ft
B.
60 ft
C.
72 ft
D.
132 ft

Answer 1

Okay, we need the formula for calculating the Area of a triangle. Any idea?

Answer 2

i dont got it

Answer 3

Well, you need to make an effort, look for it.

Answer 4

let me give you another question forget about this one

Answer 5

deal with this one first Robert

Answer 6

Are you on a test?

Answer 7

nop

Answer 8

If AB:BC is 3:11, solve for x.

A.
6
B.
9
C.
22
D.
28

Answer 9

oh

Answer 10

i dont know how to put it together

Answer 11

Sorry, that's wrong. It's this\[Area \Delta = \frac{ 1 }{ 2 } bh\]

Answer 12

1/2 4,320*6:5 like that

Answer 13

I'm wrong again. Question says rectangle. Lol

Answer 14

ok

Answer 15

So it's
Area of Rect. = Length x width

Answer 16

so its 4,320=6.5*6.5

Answer 17

Now what we're given the ration of the length to width to be 6:5. That means
\[\frac{ l }{ b } = \frac{ 6 }{ 5 }\]We get value of l by multiplying both sides by b
\[l = \frac{ 6}{ 5 }b\]

Answer 18

or going right along the path we chose, calling breadth, width
\[l = \frac{ 6}{ 5 }w\]

Answer 19

So that value will be subst in original eqn
\[Area = l \times b\]
Area = 4320ft^2, we know what l is in terms of b
Substituting...\[4320 = \frac{ 6}{ 5 }w \times w\]
\[21600 = 6w^2\]Div both sides by 6\[3600 = w^2\]Take square roots of both sides of eqn\[w = 60ft\]
So, now we've got the width. Going back to the ealier eqn we derived \[l = \frac{ 6}{ 5 }w\]Substituting w to get l\[l = \frac{ 6}{ 5 } \times 60 = 72ft\]

Answer 20

Let me know if you need any clarifications.

Answer 21

thanks

Answer 22

yw :)