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Can't get B part, I did part a but not sure if right.
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\(\vec{u}\cdot\vec{v} =|\vec{u}|\vec{v}|\cos(\theta)\) From the given question, it means that \(\cos(\theta)=1\) Think of the angle(s) which make \(\cos(\theta)=1\) true. What does that say about the position of the vectors?
would this be right? u ⃗xv ⃗=|u ⃗ ||v ⃗ | cos〖<u ⃗,v ⃗>-|u ⃗ ||v ⃗ |〗 |u ⃗ ||(v ) ⃗ |(cos<u ⃗,v ⃗> -1)=0 |u ⃗ ||v ⃗ |=0 or cos〖<u ⃗,v ⃗>-1=0〗 at least one of the two vectors is collinear and in the same direction
perps are dot products equal to 0
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