Question

Limit problem I am having trouble with...

lim (1/x - 1/8)/(x - 8)
x approaches 8

Answer 1

you have to deal with the compound fraction

Answer 2

\[\frac{1}{x}-\frac{1}{8}=\frac{8-x}{8x}\] is a start

Answer 3

okay.

Answer 4

then divide by \(x-8\) and get
\[\frac{-1}{8x}\] then replace \(x\) by \(8\)

Answer 5

Im alittle unlcear on this division step....

Answer 6

ok lets write is all

Answer 7

Thanks.

Answer 8

\[\frac{\frac{1}{x}-\frac{1}{8}}{x-8}\]
\[=\frac{\frac{8-x}{8x}}{x-8}=\frac{8-x}{8x}\times \frac{1}{x-8}\]
then since \(\frac{8-x}{x-8}=-1\) you end with
\[\frac{-1}{8x}\]