use newtons method to estimate the solutions of the equation x^2+x-1 start with x0=-1 for left and x0=1 for right hand solution find x2

Question

anonymous · Answer

$$x_2=x_1-\frac{f(x_1)}{f'(x_1)}$$ so lets compute the numbers

anonymous · Answer

if $$x_0=1$$ then $$f(1)=1+1-1=1$$ and 
$$f'(x)=2x+1$$ so $$f'(1)=3$$

anonymous · Answer

therefore 
$$x_1=1-\frac{1}{3}=\frac{2}{3}$$

anonymous · Answer

to find $x_2$ compute 
$$\frac{2}{3}-\frac{f(\frac{2}{3})}{f'(\frac{2}{3})}$$ i would use a calculator, but you could do it by hand

anonymous · Answer

and then would we do the same but with -1 in order to find the left hand solution as well?