A triangle has sides of lengths 18, 80, and 82. is ii a right triangle? Explain
answer choices: a. yes, 18^2+80^2=82^2
b.yes, 18^2+80^2=82^2
c.no, 18^2+80^2=82^2
d.no,18^2+80^2=82^2(pretend that the equal sign is crossed out)

Question

A triangle has sides of lengths 18, 80, and 82. is ii a right triangle? Explain
answer choices: a. yes, 18^2+80^2=82^2
b.yes, 18^2+80^2=82^2
c.no, 18^2+80^2=82^2
d.no,18^2+80^2=82^2(pretend that the equal sign is crossed out)

anonymous · Answer

@elementwielder   @Abbles   @McDonaldsGirl<3   @TheRealMeeeee

anonymous · Answer

are a and b the same?

abbles · Answer

You need to use the Pythagorean theorem to figure this out. a^2 + b^2 = c^2

abbles · Answer

18^2 + 80 ^2 = 82^2
Simplify this and check.  If it doesn't work out, then the triangle is not a right triangle.

anonymous · Answer

a and b are not the same one has a normal = sign the other should be crossed out

anonymous · Answer

18^2+80^2=82^2 is true

anonymous · Answer

@iambatman

abbles · Answer

What's the difference between A and B? It's one of those, the one with the regular = sign.

anonymous · Answer

ya i was wondering that earlier

anonymous · Answer

a should be a =with a/ over i b is a regular = sign

abbles · Answer

The answer is B then.

anonymous · Answer

then b is the answer

anonymous · Answer

should be a = sign with a / over it*

anonymous · Answer

oh ok then thanks @Abbles   and @elementwielder

abbles · Answer

yep :)

anonymous · Answer

welcome

anonymous · Answer

gn u guys

anonymous · Answer

nite