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sin[cos−1(−1) + 4π]
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What do you mean by cos−1(−1) ? \[\cos ^{-1}(-1)\]?
yes thats what I ment.
Do you know about the unit circle and that trigonometry is about the relationship between sides of triangle?
I know a little bit, but I do not fully understand it
I think you should read this http://www.mathsisfun.com/algebra/trigonometry.html I could just give you the answer but you will just end up hating math and suffering for it :p.
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lol thank you
Is this a multiple choice question? :P
not at all
Well you compute the equation inside the parenthesis first: arccos(-1)+4pi = 5pi Then you take the sin of that: sin(5pi) = 0 I think... lol.
omg omg your a lifesaver
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Lol, good luck with your work!
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