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Which is the equation in slope-intercept form for the line that passes through (6, 16) and is perpendicular to 2x + 5y = 4?
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If the line is perpendicular to 2x + 5y = 4 then its slope is the negative reciprocal of the line whose equation is given.
2x + 5y = 4 5y = 4 - 2x y = 4/5 - 2x/5 y = -2x/5 + 4/5 in slope-intercept form. The slope of this line is -2/5, and the negative reciprocal is 5/2, which would be the slope of any line perpendicular to this.
Using this slope and the point given, you can find the equation of the second line.
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