Please help me!!! Medal+Fanning for those who do!
Choose the equation that could be used to find three consecutive integers whose sum is 36.
n + (n + 2) + (n + 4) = 36
n + (n + 1) + (n + 3) = 36
n + (n + 1) + (n + 2) = 36
n + (n - 1) + (n - 3) = 36
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OpenStudy (anonymous):
Is it D?
OpenStudy (hoblos):
if we suppose that the smallest integer is n, what would the next integer be ?
OpenStudy (anonymous):
I'm sorry but I'm not sure about the nest integer. :(
OpenStudy (calculusxy):
Let's say that n is the number (assuming that it is 1). Consecutive to 1 are 2 and 3. If we do 1+1 we get 2 and if we do 1+2=3. Remember that n is 1. What would make sense the most?
OpenStudy (hoblos):
to get the next number, add 1 to n
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OpenStudy (anonymous):
Oh, okay. :) Thanks @hoblos and @calculusxy
OpenStudy (calculusxy):
You're welcome
OpenStudy (anonymous):
Would it B?
OpenStudy (calculusxy):
No C. See how it relates.
OpenStudy (anonymous):
Oh, yeah, sorry, didn't read that one. :(
So it's like n + (1 + 1) + (1 + 2) = 36
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