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Mathematics 8 Online
OpenStudy (anonymous):

Please help me!!! Medal+Fanning for those who do! Choose the equation that could be used to find three consecutive integers whose sum is 36. n + (n + 2) + (n + 4) = 36 n + (n + 1) + (n + 3) = 36 n + (n + 1) + (n + 2) = 36 n + (n - 1) + (n - 3) = 36

OpenStudy (anonymous):

Is it D?

OpenStudy (hoblos):

if we suppose that the smallest integer is n, what would the next integer be ?

OpenStudy (anonymous):

I'm sorry but I'm not sure about the nest integer. :(

OpenStudy (calculusxy):

Let's say that n is the number (assuming that it is 1). Consecutive to 1 are 2 and 3. If we do 1+1 we get 2 and if we do 1+2=3. Remember that n is 1. What would make sense the most?

OpenStudy (hoblos):

to get the next number, add 1 to n

OpenStudy (anonymous):

Oh, okay. :) Thanks @hoblos and @calculusxy

OpenStudy (calculusxy):

You're welcome

OpenStudy (anonymous):

Would it B?

OpenStudy (calculusxy):

No C. See how it relates.

OpenStudy (anonymous):

Oh, yeah, sorry, didn't read that one. :( So it's like n + (1 + 1) + (1 + 2) = 36

OpenStudy (anonymous):

Thanks soo much! :)

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