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Convert the equation from rectangular to polar form 9xy = 1
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you can use x = r cosA y = r sin A
\(\bf x=rcos(\theta)\qquad y=rsin(\theta) \\ \quad \\ \quad \\ 9xy = 1\implies 9[rcos(\theta)][rsin(\theta)]=1\implies [rcos(\theta)][rsin(\theta)]=\cfrac{1}{9}\) take common factor on the left-side and solve for "r"
So would it be \[ r = 1 / 9\cos(\theta)\sin(\theta)\]
yeap
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