Question

3e^(-2x+2)=6

Answer 1

@kropot72

Answer 2

3(e^(-2x)*e^(2))=6
(e^(-2x)*e^(2)=2
and then i do not know

Answer 3

\[3e ^{(-2x+2)}=6\]
Dividing both sides by 3 gives:
\[e ^{(-2x+2)}=2\]
Therefore by the laws of logarithms:
\[\ln 2=-2x+2\]
Can you solve for x now?

Answer 4

x=.65426 thank you, just checking asnwer

Answer 5

Is that correect?

Answer 6

My calculation gives x = 0.653426

Answer 7

Oops. yes , typo. thanks dude. Have a good day

Answer 8

np. You're welcome :)