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Mathematics 22 Online
OpenStudy (anonymous):

Factor the polynomial completely. That is, once you are finished factoring, none of the factors you obtain should be factorable: x^2 + 21x + bx + 21b

OpenStudy (anonymous):

(x+b)(x+21) would be the final answer x^(2)+21x+bx+21b Group the first two terms together, and group the second two terms together. (x^(2)+21x)+(bx+21b) Factor the greatest common factor (GCF) from each group. (x(x+21)+b(x+21)) Factor the polynomial by grouping the first two terms together and finding the greatest common factor (GCF). Next, group the second two terms together and find the GCF. Since both groups contain the factor (x+21), they can be combined. (x+b)(x+21)

OpenStudy (anonymous):

thank you so much :)

OpenStudy (anonymous):

You are very welcome. If you would need help in the future, Fan me now to know if I'm available/online to assist you. -- The Wonderful Adele

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