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Trigonometry
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Solve the equation graphically over the interval [0.2pi). Express solutions to the nearest hundredth. sin^3x-cosx+1=0
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Do you mean \[\sin ^{3} (x) - \cos (x) +1 = 0\]
Yes, I'm new to this, and have yet to figure out how to write the equations properly.
No problem. So this means \[\sin ^{3} (x) - \cos (x) = -1\]
If sin^3(x) = -1 and cos(x) = 0, that would work. That happens at 270 degrees.
It also happens when cos (x) = 1 and sin^3(x) = 0 which happens at 0 degrees.
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To find all the solutions, solve for x: \[\sin(x) = (-1 - cox(x))^{1/3}\]
I'm a bit stumped now.
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