who's good at algebra??
not that good
did you pass algebra 1?
yup
Maybe I can help. What do you need?
asking me
ill just post the questions will yall answer them?
yes
We're supposed to explain how to do them so that you learn. Then you will be able to get the right answers on future tests.
determine the direction in which this parabola opens y=2x*2-4x+5 up or down
@jam333 agreeded
I odnt understand it I just need the answer so I can finish this and pass please
Look at the end behaviors, The leading coefficient is positive and the degree is even so the parabola is going to open upward.
koay ask them
Wait is that y = \(\ 2x^2 - 4x + 5\) ?
yes
Then yeah, it's just as I stated above.
its an quadratic equcation u can factorise it or the formula
vertex of y=2x*2-4x+5
For the vertex, normally you would complete the square. Do you know how to do that? It becomes 2(x-1)^2 + 3. This means that the vertex is at (1,3).
The vertex can be found using \(\ -(\dfrac{b}{2a}) \) 2 is \(\ a\) -4 is \(\ b \) \(\ \sf -(\dfrac{-4}{2(2)}) \longrightarrow -(\dfrac{-4}{4}) = \dfrac{4}{4} = 1\) Now plug in 1 into f(x) = \(\ 2x^2 - 4x + 5\) f(1) = 2(1)^2 - 4(1) + 5 = ?? \(\ \sf \Large ~ Can ~ you~ solve ~ it? \)
so its (1,3)?
\(\ \sf \Large -(\dfrac{b}{2a})\) only applies to quadratic which means the degree of the polynomial is 2 (highest degree) @catking Yes the vertex is at (1,3)
what is the axis of semmitry for that equsion
Pretend you drew a big bowl on a piece of paper. The axis of symmetry is like folding the paper so that the two sides look like a mirror image of each other. If you folded along the y axis, it would not be correct. You need to fold it up and down through the vertex. So the line x = 1 would be the axis of symmetry.
I have a lot more questions if your willing to help?
determin the direction in which the parabola opens y=-2x*28x-15 up or down
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