Question

m>DXB = 70° 15' 12", m>DXC = 30° 30' 20"
m>CXB= ?

Answer 1

Sum of all angles of a triangle is = 180 degrees
Hence,

\[m \angle DXB + m \angle DXC + m \angle CXB= 180° 00' 00"\]

\[\rightarrow m \angle CXB= 180° 00' 00"-(m \angle DXB + m \angle DXC )\]
\[\rightarrow m \angle CXB= 180° 00' 00"-(70° 15' 12" + 30° 30' 20" )\]
\[\rightarrow m \angle CXB= 180° 00' 00"-100° 45' 32" \]
\[\huge \rightarrow m \angle CXB= 79° 14' 28"\] is the required answer.

@indigosonje