2 cos^2 θ + sin θ = 1 Find all solutions. I tried to substitute sin theta for x and went to 2(1-x^2) +x =1 and then factor from there. Got to sintheta = -1, -1/2, but those answers aren't working. What's my problem?
your substitution is correct
you should get 2x^2 - x -1 = 0 (2x+1)(x-1) = 0
Well, using that then, I get solutions of 3pi/2 +2pik, 11pi/6 +2pik, and 7pi/6 +2pik
it's in terms of k, and we were taught to add 2*pi*k to the end of the answer
because sin is negative in the third and fourth quadrants, i used the radians for the thirty angles in those quadrants
looks good except it should be pi/2 +2pik Not 3pi/2 ... sin theta = 1 not -1
oh whoops. It's correct now, I feel like an idiot, thank you!
haha your welcome seems like you understood the concepts, just need to check the answer may i suggest using wolframalpha.com http://www.wolframalpha.com/input/?i=2cos%5E2+x+%2B+sin+x+%3D+1
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