Solve the following quadratic equation.

Question

anonymous · Answer

$$x^{2}+2x-8=0$$

anonymous · Answer

Do You Know The Quadratic Formula?

anonymous · Answer

This Is What Your Question Looks Like, No?
$$ax^2+bx+c=0$$,

ranga · Answer

Use the "AC" method to factor.

anonymous · Answer

You Must Plug Those Numbers Into This Quadratic Formula
$$x= \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$$

anonymous · Answer

$$ax^2+b^2+c=0 
means this
 x^2+2x-8=0$$

ranga · Answer

$$x^2+2x-8 = x^2 +4x - 2x - 8$$

ranga · Answer

Factor the first two terms.  factor the last two terms.  Then factor the common term.

ranga · Answer

Quadratic formula should be the last resort.  Factoring should be tried first because in this problem it is so easy to factor.

anonymous · Answer

I'm confused.

ranga · Answer

But if there is an easier way to solve the problem, shouldn't the student be informed?
It is not about the helper.  It is what is best for the student who is looking for an answer.

Anyway, I will let you continue.

ranga · Answer

$$x^2+2x-8 = x^2 +4x - 2x - 8 = x(x+4) - 2(x+4) = (x-2)(x+4)\(x-2)(x+4) = 0\x = 2~or~x = -4$$