Suppose you have data that shows that 12% of athletes test positive for steroids. You also know that 11% of athletes test positive for steroids and actually use steroids. What is the probability that an athlete uses steroids, given that he tests positive?
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OpenStudy (anonymous):
(A).37, (B).43, (C).51, (D).67, (E).92
OpenStudy (anonymous):
im not that good so if you dont pass dont blame me so i will tell you what i think or explain
OpenStudy (anonymous):
which one
OpenStudy (anonymous):
@Mr.Man420
OpenStudy (anonymous):
@Mr.Man420 hello or i wont help
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OpenStudy (anonymous):
explain please
OpenStudy (anonymous):
@Mr.Man420 !!!!!!!!!!!!!!!!!!!!!!!!!!
OpenStudy (anonymous):
@lala525 Your too dam fast (:
OpenStudy (anonymous):
well what i see is that first i added then multiplie so what do you think like i said dont blame me cuz if you have trouble @Mr.Man420 you get a math book or something or ask someone else if the person does not know so........
OpenStudy (anonymous):
I wouldn't blame you. At least your helping.
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OpenStudy (anonymous):
:/ yeah i guess i am
OpenStudy (anonymous):
(: i really don't know where to begin tho.
OpenStudy (anonymous):
huh?
OpenStudy (anonymous):
Haha, do you know how to do the problem?
OpenStudy (anonymous):
......no only explain
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OpenStudy (anonymous):
Ok well thank you much @lala525!!
OpenStudy (anonymous):
is that in mean way or nice
OpenStudy (anonymous):
It's in a nice way(: have a great day.
OpenStudy (anonymous):
bye
OpenStudy (anonymous):
Bye
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OpenStudy (dumbcow):
this is conditional probability
\[P(A|B) = \frac{P(A and B)}{P(B)}\]
A is prob he uses steroids
B is prob he tests positive
A and B is prob he both uses and tests positive
OpenStudy (anonymous):
I'm still kinda lost. Will i use that formula to come up with the answer?
OpenStudy (anonymous):
@chineseboy15
OpenStudy (anonymous):
Would you be able to help i saw you looking?
OpenStudy (anonymous):
Let me try.
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OpenStudy (anonymous):
Ok.
OpenStudy (anonymous):
hi
OpenStudy (anonymous):
Sorry, I cannot understand this question.
OpenStudy (anonymous):
Ok thank you @chineseboy15
OpenStudy (anonymous):
@dumbcow?
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OpenStudy (anonymous):
or @lala525
OpenStudy (anonymous):
O hello @lala525(:
OpenStudy (anonymous):
hi
OpenStudy (anonymous):
didint i already help
OpenStudy (anonymous):
I don't think so(:
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OpenStudy (anonymous):
@Mr.Man420 my dude i dont know this
OpenStudy (anonymous):
I think it is D
OpenStudy (anonymous):
Ill take your word for it. How did you come up with D tho?
OpenStudy (anonymous):
its all about taking it away from 100 percent,if I remember correctly
remember,i said I think
OpenStudy (anonymous):
Yes sir.
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