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OpenStudy (anonymous):
Find an equation for the tangent to the polar curve r=1+cos(2theta) at the point where theta=pi/4
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OpenStudy (loser66):
r' =?
OpenStudy (anonymous):
i just figured it out. you cant do r'. you have to first change it into x and y. do dy/dtheta and dx/dtheta and then divide to get dy/dx and plug in pi/4. from there use point slope form to get the equation
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