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f(x)=4 times 3^x+5-6
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\[f(x)=4 \times 3^{x+5}-6\]
@myininaya
domain?
what exactly do you have to do?
domain range and asymptote
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domain (-infinity,infinity)
the inverse of y=ln(x) is y=e^x which looks like this on a graph (y=ln(x) is a reflection of y=e^x about y=x) |dw:1396990389431:dw| oops i don't have to explain the domain you got the domain great so the range now so the range for y=e^x is (0,inf) right like we can't get a negative output same thing for y=a^x where a>0 and not equal to 1 y=a^x has domain (-inf,inf) and range (0,inf) now y=(a^x)+1 has domain (-inf,inf) and range (1,inf) since each point on y=a^x was raised up once...
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