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Mathematics 17 Online
OpenStudy (anonymous):

magine taking a 10 question true or false exam. You randomly guess at each question. Don’t do any calculations, just tell me your gut sense. a) Is this a binomial setting? b) How many questions do you think you will get correct? c) How surprised would you be if you passed (6 out of 10 correct or better) the exam? d) How surprised would you be if you got an ‘A’ on the exam (9 or 10 out of 10)?

ganeshie8 (ganeshie8):

for part a, the events are equally likely and independent so its a binomial setting

ganeshie8 (ganeshie8):

for part b, should be easy for u to figure out

ganeshie8 (ganeshie8):

wat do u think ?

OpenStudy (anonymous):

Looks good to me.

OpenStudy (anonymous):

for C and D how would i do those?

ganeshie8 (ganeshie8):

depends on what u think for part b

OpenStudy (anonymous):

B would be the probability of getting on question correct

ganeshie8 (ganeshie8):

b) How many questions do you think you will get correct?

OpenStudy (anonymous):

i went with 1 out 10. but you can get any amount from 1-10

ganeshie8 (ganeshie8):

it can be any amount between 0-10 actually

ganeshie8 (ganeshie8):

u can get all questions wrong also, right ?

OpenStudy (anonymous):

yes you can.

ganeshie8 (ganeshie8):

well, but that happens only on ur greatest unluckiest rarest day

ganeshie8 (ganeshie8):

thats very unlikely to happen in general

ganeshie8 (ganeshie8):

since you have 10 questions, and each question can be either TRUE or FALSE, you have 50-50 chances for correctly ticking each question

OpenStudy (anonymous):

yeah i was thinking 10 question only true false you must get at least one correct that's why i did not think of the 0 getting all wrong

ganeshie8 (ganeshie8):

so you should expect getting ~5 questions Correct actually

ganeshie8 (ganeshie8):

getting only 0 or 1 questions correct is very UNLIKELY

ganeshie8 (ganeshie8):

so is getting 9 or 10 correct

ganeshie8 (ganeshie8):

if that makes any sense...

OpenStudy (anonymous):

it does . all about your luck ever take this kind of exam

ganeshie8 (ganeshie8):

:) so whats ur answers for b, c, d ?

OpenStudy (anonymous):

B) 5 out of 10 C) I would not be so surprised because that around how much i expecting to get correct. D) I would very surprised because it's not really likely for someone to do good on an exam like that

ganeshie8 (ganeshie8):

Looks very good !!

OpenStudy (anonymous):

thanks for the help

ganeshie8 (ganeshie8):

np :)

OpenStudy (anonymous):

can you help me with this one too. Draw a single a card from a standard deck of cards. Observe the card and then replace it. Count the number of times you draw a card like this until you get a seven

OpenStudy (anonymous):

probability of drawing one card from a deck 1 out of 52. The Count the number of times you draw a card like this until you get a seven i dont understand

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

I think it is asking u to count how many cards u need to observe until u get a 7

ganeshie8 (ganeshie8):

there are a total of 52 cards

ganeshie8 (ganeshie8):

How many cards are "7" ?

ganeshie8 (ganeshie8):

there will be FOUR cards with "7" right ?

OpenStudy (anonymous):

right

ganeshie8 (ganeshie8):

so the probability of getting a 7 is : 4/52

ganeshie8 (ganeshie8):

which is same as 1/13

ganeshie8 (ganeshie8):

so you need to draw around "13" cards to get the number 7 card

OpenStudy (anonymous):

okay

ganeshie8 (ganeshie8):

thats it, we're done.

OpenStudy (anonymous):

I thought it would be more complicated that that

ganeshie8 (ganeshie8):

hmm

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