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solve y' = (x+1)/(y-1)
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I started with integrating both sides:
Start by separating variables, yes? :)
\[\int\limits_{?}^{?}(y-1)*dy/dx=\int\limits_{?}^{?}(x+1)\]
Yeah, I multiplied (y-1) over to the dy/dx side
And then "multiply" dx to the other side, and integrate, Looks good so far.
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Alright. So \[\int\limits_{?}^{?}(y-1)*dy = \int\limits_{?}^{?}(x+1)*dx\]
and then integrate?
Yup :) Understand how to integrate each term? :o Just power rule for the most part.
yes :) thanks! I got |dw:1396995294237:dw|
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