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Mathematics 18 Online
OpenStudy (destinyyyy):

Final question-- 2 log x +logy -3 logz Need help solving or example very similar solved out

OpenStudy (loser66):

solving or simplify?

OpenStudy (destinyyyy):

Simplify

OpenStudy (loser66):

step by step, ok? I give you sample, you apply to your problem, ok?

OpenStudy (destinyyyy):

Okay. Ill tell you if im lost

OpenStudy (loser66):

\(\large \color{red}{5}log a= log a^{\color{red}{5}}\)

OpenStudy (loser66):

your turn to solve the very first step

OpenStudy (destinyyyy):

logx^2 + logy -logz^3 ??

OpenStudy (loser66):

very good, friend now, log a + log b = log a* b your turn to combine the first two terms

OpenStudy (destinyyyy):

logx^2+ log y= log xy^2 ??

OpenStudy (loser66):

hey!! how ^2 from x flip to y like that?

OpenStudy (destinyyyy):

I just transferred it over. I have no clue

OpenStudy (loser66):

if you have an umbrella while I don't, on the way we go together, the "umbrella" is yours, still, right? ^2 is the "umbrella" of x, it cannot belong to y. so that,....redo, please

OpenStudy (destinyyyy):

So logx^2y

OpenStudy (loser66):

ok, so complicated? another way to explain: I have a pimple on my face, although I go with you, my pimple is still on my face. hahahaha.. right?

OpenStudy (destinyyyy):

Thats gross and harder to follow

OpenStudy (loser66):

ok, good, now treat (x^2y ) as a "combo" log (combo) - log c = \(\large log\dfrac{combo}{c}\) your turn, combine the last one

OpenStudy (destinyyyy):

= log x^2y/ z^3 ??

OpenStudy (loser66):

bingo, you got it. congrat

OpenStudy (destinyyyy):

That's the final answer?

OpenStudy (loser66):

YYYYYYYYYYUUUUUUUUUUUP

OpenStudy (destinyyyy):

Thank you so much!!

OpenStudy (loser66):

np I will leave with my pimple, hehehehe... actually, I don't have pimple on my face, I have dimples. (2) hihihi

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