Two number cubes are rolled, one white and one yellow. Find the probability that the white cube shows a 6 and the sum is greater than 9.
On a number cube, there are six sides. On each side, there is a number. 1, 2, 3, 4, 5, 6. These are the numbers put on each side. Probability is determined by dividing the number of favorable outcomes by the number of total possible outcomes. In this case, we can see that there is only ONE six that can be displayed, and that the number of possible outcomes is equal to SIX. Probability: 1/6
For part B, determining the sum-probability, I can see that we can add 1, 2, 3, 4, 5, and 6 in 36 different ways. (I can see that because you can add 1 to 2, 3, 4, 5, and 6. That's 6 possible additions. Technically, the other numbers can be added 6 different ways as well. Adding the possible outcomes, we see that 6 + 6 + 6 + 6 + 6 + 6 comes to 36. Out of 36, 4 additions are greater than 9. 4/36 -> 2/18 -> 1/9. So the probability is 1/9 that the sum is greater than 9. I might be wrong, tell me if I am and I'll think it through some more.
It's not 1/9
Hm....I'm gonna have to think this one through a bit.
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