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Mathematics 24 Online
OpenStudy (anonymous):

In the figure below, ΔABC ≅ ΔDEF. Point C is the point of intersection between segment AG and segment BF while point E is the point of intersection between segment DG and segment BF.

OpenStudy (anonymous):

OpenStudy (anonymous):

Prove ΔABC ~ ΔGEC.

OpenStudy (anonymous):

@kewlgeek555 can you help?

OpenStudy (anonymous):

@mathmale

OpenStudy (anonymous):

@mathslover

OpenStudy (anonymous):

@iPwnBunnies

OpenStudy (anonymous):

@Zale101

OpenStudy (anonymous):

@nincompoop pleaseeeee

OpenStudy (anonymous):

I swear to god if someone doesnt help me im gonna cry

OpenStudy (anonymous):

someone please

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

lol you still looking for help on this question?

OpenStudy (anonymous):

@whpalmer4

OpenStudy (anonymous):

YES

OpenStudy (anonymous):

where the other answers not helpful?

OpenStudy (anonymous):

I dont understand it. But whatever. I'm about to give up.

OpenStudy (anonymous):

*were

OpenStudy (anonymous):

lol id say what i said before but you said you didnt learn what i was talking about yet

jimthompson5910 (jim_thompson5910):

|dw:1397009407300:dw|

OpenStudy (anonymous):

I know angle e=b g=a and c=c

jimthompson5910 (jim_thompson5910):

we are given that ΔABC ≅ ΔDEF, so by CPCTC, we know angle ABC = angle DEF and angle ACB = angle DFE

OpenStudy (anonymous):

Si. okay that makes sense

jimthompson5910 (jim_thompson5910):

let's mark the drawing to update the fact that angle ABC = angle DEF |dw:1397009551237:dw|

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