In the figure below, ΔABC ≅ ΔDEF. Point C is the point of intersection between segment AG and segment BF while point E is the point of intersection between segment DG and segment BF.
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OpenStudy (anonymous):
OpenStudy (anonymous):
Prove ΔABC ~ ΔGEC.
OpenStudy (anonymous):
@kewlgeek555 can you help?
OpenStudy (anonymous):
@mathmale
OpenStudy (anonymous):
@mathslover
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OpenStudy (anonymous):
@iPwnBunnies
OpenStudy (anonymous):
@Zale101
OpenStudy (anonymous):
@nincompoop pleaseeeee
OpenStudy (anonymous):
I swear to god if someone doesnt help me im gonna cry
OpenStudy (anonymous):
someone please
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OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
lol you still looking for help on this question?
OpenStudy (anonymous):
@whpalmer4
OpenStudy (anonymous):
YES
OpenStudy (anonymous):
where the other answers not helpful?
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OpenStudy (anonymous):
I dont understand it. But whatever. I'm about to give up.
OpenStudy (anonymous):
*were
OpenStudy (anonymous):
lol id say what i said before but you said you didnt learn what i was talking about yet
jimthompson5910 (jim_thompson5910):
|dw:1397009407300:dw|
OpenStudy (anonymous):
I know angle e=b g=a and c=c
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jimthompson5910 (jim_thompson5910):
we are given that ΔABC ≅ ΔDEF, so by CPCTC, we know
angle ABC = angle DEF
and
angle ACB = angle DFE
OpenStudy (anonymous):
Si. okay that makes sense
jimthompson5910 (jim_thompson5910):
let's mark the drawing to update the fact that angle ABC = angle DEF
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