Question

how do you simplify 16 plus or minus the square root of 32 all over 14

Answer 1

\[62=16\times 2\] so
\[\sqrt{32}=\sqrt{16}\sqrt2=4\sqrt2\] is a start

Answer 2

you have
\[\frac{16\pm\sqrt{32}}{14}=\frac{16\pm4\sqrt2}{14}=\frac{2(8+2\sqrt2)}{14}\] then cancel the 2 top and bottom

Answer 3

so the final result is ?