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Mathematics 15 Online
OpenStudy (anonymous):

does someones know how to solve these? (geometry)

OpenStudy (anonymous):

OpenStudy (nikato):

Remember the area of a sector= 1/2 ( radius x length of arc)

OpenStudy (nikato):

Or in your problem you would use Area of sector= (arc measure/360) x pi(r^2)

OpenStudy (anonymous):

whats the number for the arc

OpenStudy (nikato):

So do you know what the radius is? And the measure of the arc containing point E?

OpenStudy (anonymous):

10?

OpenStudy (nikato):

To find the measure of the arc, you must know what kind of angle AGB is

OpenStudy (anonymous):

i dont know the measure of the arc containg point E

OpenStudy (anonymous):

???

OpenStudy (nikato):

Hint: it's a central angle

OpenStudy (nikato):

If its a central angle, what do you know about the intercepted arc?

OpenStudy (anonymous):

i dont know...

OpenStudy (nikato):

It would be the same. The intercepted arc of a central angle has the same measure of that angle

OpenStudy (anonymous):

is it like a part of the circle between the intersection

OpenStudy (anonymous):

oh ok

OpenStudy (nikato):

I'm not sure what you mean by intersection But The measure of that arc would be 72

OpenStudy (anonymous):

so 72/360 x π10^2=62.8... did i do that right?

OpenStudy (anonymous):

would 62.8 be my final answer?

OpenStudy (anonymous):

how would i solve this...sorry i dont feel that ready solving problem like these

OpenStudy (anonymous):

@nikato

OpenStudy (nikato):

Yes. 62.8 is correct

OpenStudy (anonymous):

how do i solve the second attachment?

OpenStudy (nikato):

First draw in DG, GF, and GE

OpenStudy (anonymous):

ok

OpenStudy (nikato):

And now you have 6 right triangles, right?

OpenStudy (anonymous):

right

OpenStudy (nikato):

What do you know triangle DGC and FGC?

OpenStudy (anonymous):

DGC and FGC are the same right?

OpenStudy (nikato):

You mean congruent. And if that's true, what do you about sides DC and CF

OpenStudy (anonymous):

that they are the same length?

OpenStudy (nikato):

Correct. So if DC=21 , then what's CF?

OpenStudy (anonymous):

21

OpenStudy (nikato):

Yes. So CB=?

OpenStudy (anonymous):

21*2=42

OpenStudy (nikato):

No. It's CF+FB. So 21+20=41 So CB=41

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

so 41 is teh final answer?

OpenStudy (nikato):

Can you do the same with triangle FGB and EGB to find side EB?

OpenStudy (nikato):

And no, 41 is just the length of one of the sides

OpenStudy (anonymous):

wouldnt it be the same number?

OpenStudy (nikato):

No. It wouldn't

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

42

OpenStudy (nikato):

Yup. So can you do that whole process again to find EB

OpenStudy (nikato):

Wait, how did you get 42

OpenStudy (anonymous):

22

OpenStudy (nikato):

Wait, 22 for what?

OpenStudy (anonymous):

sorry, my computer keeps freezing and it takes forever for my answer to show up so just ignore 22 and 42

OpenStudy (anonymous):

how do i find EB

OpenStudy (anonymous):

EB=20?

OpenStudy (nikato):

It's fine. And yes EB=20. So now what's AE?

OpenStudy (anonymous):

AE=32

OpenStudy (nikato):

And doing the same thing as before, what's AD?

OpenStudy (anonymous):

AD=31?

OpenStudy (nikato):

You mean 32. And what's AC?

OpenStudy (anonymous):

oh yes! and 32+21=53 AC=53

OpenStudy (anonymous):

so then 52+53+41=146 the answer?

OpenStudy (nikato):

Correct!

OpenStudy (anonymous):

yes! now i get how to solve these problems! thank you thankyou!

OpenStudy (nikato):

No problem. And doin more problem will surely help

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