Mathematics
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OpenStudy (anonymous):
does someones know how to solve these? (geometry)
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OpenStudy (anonymous):
OpenStudy (nikato):
Remember the area of a sector= 1/2 ( radius x length of arc)
OpenStudy (nikato):
Or in your problem you would use
Area of sector= (arc measure/360) x pi(r^2)
OpenStudy (anonymous):
whats the number for the arc
OpenStudy (nikato):
So do you know what the radius is?
And the measure of the arc containing point E?
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OpenStudy (anonymous):
10?
OpenStudy (nikato):
To find the measure of the arc, you must know what kind of angle AGB is
OpenStudy (anonymous):
i dont know the measure of the arc containg point E
OpenStudy (anonymous):
???
OpenStudy (nikato):
Hint: it's a central angle
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OpenStudy (nikato):
If its a central angle, what do you know about the intercepted arc?
OpenStudy (anonymous):
i dont know...
OpenStudy (nikato):
It would be the same.
The intercepted arc of a central angle has the same measure of that angle
OpenStudy (anonymous):
is it like a part of the circle between the intersection
OpenStudy (anonymous):
oh ok
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OpenStudy (nikato):
I'm not sure what you mean by intersection
But
The measure of that arc would be 72
OpenStudy (anonymous):
so 72/360 x π10^2=62.8... did i do that right?
OpenStudy (anonymous):
would 62.8 be my final answer?
OpenStudy (anonymous):
how would i solve this...sorry i dont feel that ready solving problem like these
OpenStudy (anonymous):
@nikato
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OpenStudy (nikato):
Yes. 62.8 is correct
OpenStudy (anonymous):
how do i solve the second attachment?
OpenStudy (nikato):
First draw in DG, GF, and GE
OpenStudy (anonymous):
ok
OpenStudy (nikato):
And now you have 6 right triangles, right?
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OpenStudy (anonymous):
right
OpenStudy (nikato):
What do you know triangle DGC and FGC?
OpenStudy (anonymous):
DGC and FGC are the same right?
OpenStudy (nikato):
You mean congruent.
And if that's true, what do you about sides DC and CF
OpenStudy (anonymous):
that they are the same length?
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OpenStudy (nikato):
Correct. So if DC=21 , then what's CF?
OpenStudy (anonymous):
21
OpenStudy (nikato):
Yes. So CB=?
OpenStudy (anonymous):
21*2=42
OpenStudy (nikato):
No. It's CF+FB.
So
21+20=41
So
CB=41
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OpenStudy (anonymous):
oh
OpenStudy (anonymous):
so 41 is teh final answer?
OpenStudy (nikato):
Can you do the same with triangle FGB and EGB to find side EB?
OpenStudy (nikato):
And no, 41 is just the length of one of the sides
OpenStudy (anonymous):
wouldnt it be the same number?
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OpenStudy (nikato):
No. It wouldn't
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
42
OpenStudy (nikato):
Yup. So can you do that whole process again to find EB
OpenStudy (nikato):
Wait, how did you get 42
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OpenStudy (anonymous):
22
OpenStudy (nikato):
Wait, 22 for what?
OpenStudy (anonymous):
sorry, my computer keeps freezing and it takes forever for my answer to show up so just ignore 22 and 42
OpenStudy (anonymous):
how do i find EB
OpenStudy (anonymous):
EB=20?
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OpenStudy (nikato):
It's fine. And yes EB=20.
So now what's AE?
OpenStudy (anonymous):
AE=32
OpenStudy (nikato):
And doing the same thing as before, what's AD?
OpenStudy (anonymous):
AD=31?
OpenStudy (nikato):
You mean 32.
And what's AC?
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OpenStudy (anonymous):
oh yes! and 32+21=53 AC=53
OpenStudy (anonymous):
so then 52+53+41=146 the answer?
OpenStudy (nikato):
Correct!
OpenStudy (anonymous):
yes! now i get how to solve these problems! thank you thankyou!
OpenStudy (nikato):
No problem. And doin more problem will surely help