Question

10.
Determine the number of real solutions of -2x2 + 5x - 3 = 0.


A. 0
B. 1 (double root)
C. 2

Answer 1

you can't factor this, completing the square would be hard to do; so I suggest to use a QUADRATIC FORMULA.

Answer 2

okay and how would i set it up?

Answer 3

\(\Large\color{blue}{ \bf \color{red} { a }x^2+\color{green} { b }x+\color{black} { c }=0 }\)

\(\Large\color{blue}{ \bf \color{red} { -2 }x^2\color{green} { +5 }x+\color{black} { -3 }=0 }\)



\(\Huge\color{blue}{ \bf \frac{-b± \sqrt{ b^2-4ac} }{2a} }\)

Answer 4

See how to compare the "a", "b", "c" and how to plug them in ?

Answer 5

The second equation is just -3, not +-3. sorry about that.

Answer 6

im goingto try to solve it now

Answer 7

yes, and I would prefer you to show the steps in here, if you will. you don't have to though.

Answer 8

\[-3\sqrt{-2}^{2}-4(-2*3) \] @SolomonZelman

Answer 9

you can use \frac{ }{ } as a fraction

♂ ♂
top bottom

Answer 10

\(\Huge\color{purple}{ \sf ∠ \frac{-5±\sqrt{(5)^{2}- 4(-2)(-3) } }{2(-2)} }\)