Solve by taking the square roots of both sides.

(x + 4)2 - 5 = 2

FOR MY ANSWER I GOT X=4+√ 7, X=-4+√ 7
BUT MY TEACHER SAID IM WRONG

Question

Solve by taking the square roots of both sides.

(x + 4)2 - 5 = 2

FOR MY ANSWER I GOT X=4+√ 7, X=-4+√ 7
BUT MY TEACHER SAID IM WRONG

anonymous · Answer

go to www.purplemath.com/modules/solvquad2.htm

anonymous · Answer

it has videos to help

solomonzelman · Answer

$\Huge\color{blue}{ \it       (x+4)^2-5=2 }$

1)  add 5 to both sides
2)  take the square root of both sides
3)  subtract 4 from both sides.

you are correct, but one more addition...

$\Huge\color{blue}{ \it       x=-4±\sqrt{7 } }$

4 is always negative, 7 is ±.

solomonzelman · Answer

Do you see hwy the teachers say that you are wrong ? They are correct.... -:(

solomonzelman · Answer

actually it's only 1 teacher.

solomonzelman · Answer

Good luck !

anonymous · Answer

try the website ambbiiee

anonymous · Answer

X=3,X=-11 @SolomonZelman

solomonzelman · Answer

Noo !
you are completing the square. @Ambbiiee can we start over, b/c you seem to lose me overhere.

solomonzelman · Answer

$\Huge\color{blue}{ \rm  (x + 4)^2 - 5 = 2 }$

@Ambbiiee , show me what you get after you add 5 to both sides please.

anonymous · Answer

SEARCH ON GOOGLE X+4 IT WILL SHOW A GRAPH

anonymous · Answer

|dw:1397048130210:dw|
@SolomonZelman

anonymous · Answer

try the website ambbiiee

solomonzelman · Answer

I got disconnected, sorry -:(
$\Huge\color{blue}{ \sf    (x+4)^2=7 }$

yes, that's correct.

Now, square root  both sides,