Can anyone help me with this? I dont want answers just how to figure it out. The picture shows a triangular island. Which expression shows the value of e? f sin 65°, f cos 65°, d over cos 65 degrees, and d over sin 65 degrees.
do u wanna know what sin and cos means?
If you have time, see http://www.khanacademy.org/math/trigonometry/basic-trigonometry/basic_trig_ratios/v/basic-trigonometry
here is an example of using trig to answer questions on a test http://www.khanacademy.org/math/geometry/geometry-worked-examples/v/ca-geometry--more-trig
I know what they are. but, I don't understand it with the letters in front of the equation and stuff.
the letters are just a way of representing the angles
Which expression shows the value of e? You are given angle 65º, and you want to find side e that means you need to use the trig ratio that uses side "e" e is the hypotenuse. which ratios use the hypotenuse ?
sin and cos. right? sin=opp/hyp and cos=adj/hyp.
yes. now for angle 65º, hyp is e. what side is opp ?
angle f. so it'd be sin65=f/e?
side f. so you have sin65 = f/e can you solve for e ?
Wouldn't I have to multiply f by both sides to solve for e?
if you multiply both sides by f you get \[ f \sin65 = \frac{f}{e} \cdot f \] which is not helpful. on the other hand if you multiply both sides by e \[ e \sin65 = \frac{f}{e} \cdot e \] the e's on the right side "cancel out" because e/e= 1
now divide both sides by sin65 to get e by itself.
Oh! okay. I get it. (: Thank you.
you get e = f/sin65 but that is not one of your choices. We should look at using cos65= d/e
Okay, so, do the same thing but with cos65=d/e?
yes. another way to solve for e is "flip" both sides to get \[ \frac{1}{\cos65}= \frac{e}{d} \]
to "cancel out" the d on the right side, multiply by d. To keep things equal, we multiply both sides by d.
Okay. That makes much more sense now. Thank you so much.
can you answer the question ?
Yes. it's e=d/cos65. right?
yes.
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