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Mathematics 21 Online
OpenStudy (linn99123):

What is the approximate area of the figure? A. 129 square inches B. 113 square inches C. 110 square inches D. 44 square inches http://static.k12.com/calms_media/media/1419000_1419500/1419369/1/86647ce2ff60b5259f618a72b06ef68e4106d3cc/MS_PA_130922_171140.jpg I chose answer A

OpenStudy (punksauce):

I believe it is also A but let me check again..

OpenStudy (anonymous):

A is correct

OpenStudy (anonymous):

A is correct, and you are hot

OpenStudy (anonymous):

A is not correct: Area of the rectangle: \[A=wl\]\[A=7*13=91\] Area of the half-circle: \[A=\frac{1}{2}*\pi*r^{2}\]\[A=\frac{1}{2}\pi*3.5^{2}=19.23\] Total area: \[A=A1+A2=91+19.24=110.23\] The answer is C. A would be right if it was a FULL circle, but its not.

OpenStudy (anonymous):

7*13 would be the area of the Rectangle. That comes to 91. Keep that in back of your head. If you take a close look at the semi-circle, you'll see that the diameter is 7 inches. Imagine a whole circle with radius (7/2) inches, or 3.5 inches. Pi*(radius^2) = area, so 3.14*(3.5^2) = a total area of 38.48. But this is a half-circle. Not a whole circle. So divide the total area in half to get: 19.24 inches. Take this area of the semicircle and add it to the area of the rectangle. That'd be 91+19.24: You get 110.24 inches sqt. Twvogels is right, y'all.

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