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OpenStudy (anonymous):
how can I solve w^3=1 if I know that w=z1/a (z^2+az+a^2=0 with z1 the solution of this equasion )
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OpenStudy (agent0smith):
First write it as w^3 - 1 = 0 Then you can factor using a difference of two cubes (or use division), and solve the quadratic. I can't really tell what you've posted, but this will work.
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