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Find the standard form of the following equation. y=(x+3)^2+1 Pls Help
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Standard form is \(\large Ax^2+Bx+C\)
*\(\large =y\)
\[ y=x ^{2}+9x+1?\]
No, you made a common booboo >.<
y = (x + 3)(x + 3) + 1
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Try Foiling (x + 3)(x + 3) first
\((a+b)^2 \neq a^2+b^2\)
ohh ok so that would make it \[y=x ^{2}+3x+9?\]
And then +1
making it \[y=x ^{2}+3x+10?\]
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Yup~
Wait, check your middle term.
\[6x\]
Now it's right :)
Thank you so much!! @Luigi0210
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