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y=x4+4x, dx/dt=4 and x+1. how do i find dy/dt?
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Just write it... \(\dfrac{dy}{dt} = 4x^{3}\cdot \dfrac{dx}{dt} + 4\dfrac{dx}{dt}\) I'm not sure what the "x+1" is. If the problem is not presented correctly, that could make it more difficult.
oh sorry it was supposed to be x=1
thank you! i forgot 4(dx/dt)
its still saying its wrong :/
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is that copied correctly?
yeah
|dw:1397095804672:dw|
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