A box contains 15 cards. There are 5 red cards labeled 1, 2, 3, 4, and 5. There are 5 blue cards labeled 1, 2, 3, 4, and 5. There are 5 green cards labeled 1, 2, 3, 4, and 5. One card is drawn from the box. What is the probability that it is a green card with an even number or a blue card? A) 2/45 B) 2/3 C) 1/3 D) 7/15 Please and thank you! Have a good day :):):):):)
ooo lots of colors =D Because the events are mutually exclusive ("even green card" and "blue card") you add the probability of the individual events.
@JoelSjogren i still dont get it sorry :(
Maybe that logic is unnecessary. I'll try with something better.
@JoelSjogren hahahahah ya. i know :/ i wish its kinda a weird question
When you draw a card, there are a certain number of outcomes that is satisfies the conditions in the question, and there are 15 outcomes in total. Divide the first number by the second to get the probability.
uh what? @JoelSjogren
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@JoelSjogren oh my gosh thank you so much! that really helped alot! i gave you a metal and everything!!! thanks!! i also added you as a fan :):):)
I'm glad to have helped!
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