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OpenStudy (anonymous):
Simplify the expression.
cos^2 x + sin^2 x/cot^2 x - csc^2 x
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OpenStudy (anonymous):
Do you mean this :
\[frac{cos^2( x) + sin^2 (x)}{cot^2 (x) - cosec^2 (x)}\]
OpenStudy (anonymous):
No. I mean this: \[ \frac{ \cos ^{2} x + \sin ^{2} x}{ \cot ^{2} x - \csc ^{2} x }\]
OpenStudy (anonymous):
@waterineyes
OpenStudy (anonymous):
I am seeing Math Processing Error.. Just wait I am refreshing my page so that Latex can upload properly..
OpenStudy (anonymous):
Okay :)
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OpenStudy (anonymous):
Yeah I was almost there.. :)
OpenStudy (anonymous):
Do you know about Trigonometric Identities??
OpenStudy (anonymous):
Kind of
OpenStudy (anonymous):
I mean you must remember these:
\[1. \quad \sin^2(x) + \cos^2(x) = 1\]
\[2. \quad 1 + \tan^2(x) = \sec^2(x)\]
\[3. \quad 1 + \cot^2(x) = cosec^2(x)\]
OpenStudy (anonymous):
Remember??
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OpenStudy (anonymous):
Sooo it'd be 1?
OpenStudy (anonymous):
No wait, would it be -1 because I'm dividing?
OpenStudy (anonymous):
@waterineyes
OpenStudy (anonymous):
Numerator will give you 1 but denominator will give you -1.. So 1 divided by -1 will be how much??
OpenStudy (anonymous):
-1
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OpenStudy (anonymous):
@waterineyes
OpenStudy (anonymous):
Excellent... :)
OpenStudy (anonymous):
Thanks
OpenStudy (anonymous):
Welcome dear..
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